pKa = 3.5 c=10**(-linspace(0,6)) H=ConcentrationOxonium(c, Ka=10**(-pKa)) # Note: p(c) = -log10(c) plot(p(c),p(H),lw=3,color='red',zorder=1) plot(p(c),.5*(pKa+p(c))) plot(p(c),p(c)) xlabel("pc") ylabel("pH") Prepamath downloader

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